Dear my friends, How can I efficiently linearize the following logical constraint?

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asked 10 Jul '15, 12:03

monash's gravatar image

monash
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is x nonnegative?

(10 Jul '15, 13:01) Ayhan

@Ayhan: yes, x is nonnegative.

(10 Jul '15, 13:20) monash

You can't, at least not exactly. If you're willing to accept an approximate solution (ruling out very small positive values for \(x\), then this is a FAQ; a bit of searching should turn up one or more answers.

link

answered 10 Jul '15, 16:15

Paul%20Rubin's gravatar image

Paul Rubin ♦♦
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accept rate: 19%

2

\( \epsilon - M \leq x - M\cdot y \leq 0 \)

(13 Jul '15, 18:08) Slavko

@Slavko: Why don't you express your comment as an answer? I really liked it!

(14 Jul '15, 11:17) monash

Since my comment is only a complement to the above answer Prof. @Paul Rubin. All my statements in questions like "How to linearize ..." are based on previous entries mentioned by Prof. @Paul Rubin.

(16 Jul '15, 12:22) Slavko
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Asked: 10 Jul '15, 12:03

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Last updated: 16 Jul '15, 12:23

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